Integrating curvatures over beam length, the deflection, at some point along x-axis, should also be reversely proportional to I. Therefore, it can be seen from the former equation, that when a certain bending moment M is applied to a beam cross-section, the developed curvature is reversely proportional to the moment of inertia I. Where Ixy is the product of inertia, relative to centroidal axes x,y, and Ixy' is the product of inertia, relative to axes that are parallel to centroidal x,y ones, having offsets from them d_. The differential element dA has width dx and height dy, so dA dx dy dy dx. Where I' is the moment of inertia in respect to an arbitrary axis, I the moment of inertia in respect to a centroidal axis, parallel to the first one, d the distance between the two parallel axes and A the area of the shape (=bh in case of a rectangle).įor the product of inertia Ixy, the parallel axes theorem takes a similar form: To find the moment of inertia, divide the area into square differential elements dA at (x, y) where x and y can range over the entire rectangle and then evaluate the integral using double integration. The so-called Parallel Axes Theorem is given by the following equation: The moment of inertia of any shape, in respect to an arbitrary, non centroidal axis, can be found if its moment of inertia in respect to a centroidal axis, parallel to the first one, is known.
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